HTC Incredible 2
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android.content.ActivityNotFoundException: Unable to find explicit activity class {com.example.my_package/com.example.my_package.MainClass}; have you declared this activity in your AndroidManifest.xml?
Is MainClass.java in AndroidManifest as a activity ?
AndroidManifest.xml example
Is MainClass.java in AndroidManifest as a activity ?
AndroidManifest.xml example
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="//schemas.android.com/apk/res/android"
package="com.example.my_packag"
android:versionCode="1"
android:versionName="1.0">
<uses-sdk android:minSdkVersion="7" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".MainClass"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
if , else if, else statement with string as a switch statement in Java example source code.
MainClass.java
MainClass.java
public class MainClass {
public static void main(String[] arg) {
String[] arrayOfString = {"nothing", "Hello", "people"
, "bye-bye", "hello", "world!", "end" };
for (int i = 0; i < arrayOfString.length; i++) {
if (arrayOfString[i].equals("Hello"))
System.out.println(arrayOfString[i]);
else if (arrayOfString[i].equals("people"))
System.out.println(arrayOfString[i]);
else if (arrayOfString[i].equals("hello"))
System.out.println(arrayOfString[i]);
else if (arrayOfString[i].equals("world!"))
System.out.println(arrayOfString[i]);
else // default
System.out.println("Default");
}
}
}
/*
Default
Hello
people
Default
hello
world!
Default
*/
While cycle Java basic example with array of strings.
MainClass.java
MainClass.java
public class MainClass {
public static void main(String[] arg) {
String[] arrayOfString = { "Hello", "people", "hello", "world!" };
int i = 0;
while ( i < arrayOfString.length ){
System.out.println(arrayOfString[i]);
i++;
}
}
}
Table of usability phones with Android: (Our software)
Graph of usability Smartphone with Android - October 2011:
Samsung Galaxy S2 vs iPhone4 - browsing, gaming, apps, performance, browser, fast, against, navigation, Sygic, apk, Android, iOS
October 2011 | September 2011 | ||||||||||||||||||||||||||||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
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Graph of usability Smartphone with Android - October 2011:

Samsung Galaxy S2 vs iPhone4 - video
Samsung Galaxy S2 vs iPhone4 - browsing, gaming, apps, performance, browser, fast, against, navigation, Sygic, apk, Android, iOS
Get key by value from Map Java Android example
MainClass.java
MainClass.java
import java.util.HashSet;
import java.util.Iterator;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
import java.util.TreeMap;
public class MainClass {
public static void main(String[] arg) {
// english;germany dictionary
String[] arrayOfString = { "one;eine", "two;zwei", "two sets of;zwei"
, "three;drei", "four;vier" };
Map<String, String> map = new TreeMap<String, String>();
for (String s : arrayOfString) {
String[] array = s.split(";");
String sKey = "", sValue = "";
if (array.length > 1) {
sKey = array[0];
sValue = array[1];
map.put(sKey, sValue);
}
}
if (map.containsValue("zwei")) {
Set<String> references = getKeysByValue(map, "zwei");
Iterator<String> it = references.iterator();
while (it.hasNext()) {
String key = (String) it.next();
String value = map.get(key);
System.out.println(key + " = " + value);
}
}
}
public static <T, E> Set<T> getKeysByValue(Map<T, E> map, E value) {
Set<T> keys = new HashSet<T>();
for (Entry<T, E> entry : map.entrySet()) {
if (entry.getValue().equals(value)) {
keys.add(entry.getKey());
}
}
return keys;
}
}
/*
two = zwei
two sets of = zwei
*/
Editace: 2012-02-22 12:54:56
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