Cursor managedQuery Deprecated
Try this code with CursorLoader:
Uri uri = getIntent().getData();
// DEPRECATED
Cursor cursor = managedQuery(uri, null, null, null, null);
// WORKING - loadInBackground() preventing freezing of app
Cursor cursor = new CursorLoader(getApplicationContext(),uri, null, null, null, null).loadInBackground();
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Android development
long is 64 bit signed type and used when int is not large enough to hold the value.
long je celé číslo 64 bitů -9223372036854775808 +9223372036854775807 a používá se tam, kde typ int není schopen pojmout takovou hodnotu čísla.
long is 64 bit signed type and used when int is not large enough to hold the value.
long je celé číslo 64 bitů -9223372036854775808 +9223372036854775807 a používá se tam, kde typ int není schopen pojmout takovou hodnotu čísla.
// declaration and assignment of value type long
long n = 22337203685477580L;
// print formated value
System.out.printf("The value of x is %d%n", n); // 22337203685477580
System.out.format("%+,8d%n%n", n); // +22 337 203 685 477 580
// declaring more variables in single statement
long lo1 = 12L, lo2 = 56, lo3 = 1455555555589L;
// long range of value
System.out.println(Long.MAX_VALUE); // 9223372036854775807
System.out.println(Long.MIN_VALUE); // -9223372036854775808
// check if a string is a valid number in Java example
// convert string to long Java example
String sLong = "1288888888888888";
long longParse = Long.parseLong(sLong);
// convert strings to numbers
long longFromString = (Long.valueOf(sLong)).longValue();
// long to string in Java example code
Long longObj = new Long(229999999999L);
String str = longObj.toString();
// else
Long longS = 888888888888L;
String strLong = longS.toString();
// compare two long variables
Long longComp1 = 5555L;
if (longComp1.equals(55555555L))
System.out.print("true");
// compares the two specified long values in Java example
int i = longS.compareTo(444444L); // -1 first < second
// 0 first == second
// 1 first > second
System.out.print(i);
If the app have transparent menu and you do not want this,
try delete @style/AppTheme in application tag in AndroidManifest.xml
and try run module - project. If menu is not transparent , maybe it caused
Or try set values\styles.xml into basic Theme
try delete @style/AppTheme in application tag in AndroidManifest.xml
and try run module - project. If menu is not transparent , maybe it caused
<application
android:allowBackup="true"
android:icon="@drawable/dicts_ico"
android:label="@string/app_name"
android:theme="@style/AppTheme" // delete this row - run app - try menu
>
Or try set values\styles.xml into basic Theme
<resources>
<!--
Base application theme, dependent on API level. This theme is replaced
by AppBaseTheme from res/values-vXX/styles.xml on newer devices.
-->
<style name="AppBaseTheme" parent="android:Theme.Black">
<!--
Theme customizations available in newer API levels can go in
res/values-vXX/styles.xml, while customizations related to
backward-compatibility can go here.
-->
</style>
<!-- Application theme. -->
<style name="AppTheme" parent="AppBaseTheme">
<!-- All customizations that are NOT specific to a particular API-level can go here. -->
</style>
</resources>
ListFragment show only one item issue
Try to change layout_width to 0dp
Try to change layout_width to 0dp
<fragment android:name="cz.okhelp.android.fragchangfromlist.ArticleFragment"
android:id="@+id/article_fragment"
android:layout_weight="2"
android:layout_width="0dp"
android:layout_height="match_parent" />
<!--todo LAYOUT_WIDTH have to be 0dp !!!!!!!!!!!!!!!!!!!!! -->
<FrameLayout android:id="@+id/article_fragment"
android:layout_width="0dp"
android:layout_height="match_parent"
android:layout_weight="2" />
For and continue statement in Java.
public class MainClass {
public static void main(String[] arg) {
String[] arrayOfString = { "Hello", "people", "hello", "world!" };
for (int i = 0; i < arrayOfString.length; i++){
if(arrayOfString[i].equals("hello"))
continue; // skip to for
System.out.println(arrayOfString[i]);
}
}
}
/*
Hello
people
world!
*/
import android.os.Build.VERSION;
//
int nSdkVersion = Integer.parseInt(Build.VERSION.SDK);
int nApiVersion = VERSION.SDK;
Platform Version | API Level |
---|---|
Android 4.0 | 14 |
Android 3.2 | 13 |
Android 3.1.x | 12 |
Android 3.0.x | 11 |
Android 2.3.4 | 10 |
Android 2.3.3 | 10 |
Android 2.3.2 | 9 |
Android 2.3.1 | 9 |
Android 2.3 | 9 |
Android 2.2.x | 8 |
Android 2.1.x | 7 |
Android 2.0.1 | 6 |
Android 2.0 | 5 |
Android 1.6 | 4 |
Android 1.5 | 3 |
Android 1.1 | 2 |
Android 1.0 | 1 |
Editace: 2015-11-07 11:28:26
Počet článků v kategorii: 396
Url:cursor-managedquery-deprecated