Create monochromatic bitmap Android example
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(new SampleView(this));
}
private static class SampleView extends View {
// CONSTRUCTOR
public SampleView(Context context) {
super(context);
setFocusable(true);
}
@Override
protected void onDraw(Canvas canvas) {
Paint paint = new Paint();
canvas.drawColor(Color.GREEN);
Bitmap b = Bitmap.createBitmap(200, 200, Bitmap.Config.ALPHA_8);
paint.setColor(Color.BLUE);
Canvas c = new Canvas(b);
c.drawRect(0, 0, 200, 200, paint);
canvas.drawBitmap(b, 10,10, paint);
}
}
}
396LW NO topic_id
AD
Další témata ....(Topics)
LayoutLib is too recent. Update your tool!
Eclipse Android Graphical layout resolving problem.
Eclipse Android Graphical layout resolving problem.
- Open in Eclipse menu Help ->Check for Updates
- Select updates:
- Press Next and update all
- Restart Eclipse
[caption id="attachment_596" align="alignleft" width="300" caption="Restart Eclipse if updates finished."]
[/caption]
Map TreeMap sorted by value Java Android example.
MainClass.java
MainClass.java
import java.util.Comparator;
import java.util.Map;
import java.util.Map.Entry;
import java.util.SortedSet;
import java.util.TreeMap;
import java.util.TreeSet;
public class MainClass {
public static void main(String[] arg) {
// english;germany dictionary
String[] arrayOfString = { "one;eine", "two;zwei", "three;drei",
"four;vier" };
Map<String, String> map = new TreeMap<String, String>();
for (String s : arrayOfString) {
String[] array = s.split(";");
String sKey = "", sValue = "";
if (array.length > 1) {
sKey = array[0];
sValue = array[1];
map.put(sKey, sValue);
}
}
for (Entry<String, String> entry: mapSortedByValues(map)) {
System.out.println(entry.getKey() + " = " + entry.getValue());
}
}
static <K, V extends Comparable<? super V>> SortedSet<Map.Entry<K, V>> mapSortedByValues(
Map<K, V> map) {
SortedSet<Map.Entry<K, V>> sortedSetOfEntries = new TreeSet<Map.Entry<K, V>>(
new Comparator<Map.Entry<K, V>>() {
@Override
public int compare(Map.Entry<K, V> entry_1, Map.Entry<K, V> entry_2) {
int res = entry_1.getValue().compareTo(entry_2.getValue());
return res != 0 ? res : 1;
// return entry_1.getValue().compareTo(entry_2.getValue());
}
});
sortedSetOfEntries.addAll(map.entrySet());
return sortedSetOfEntries;
}
}
/*
three = drei
one = eine
four = vier
two = zwei
*/
Basic difference remember it!!!
if(TRUE && TRUE && TRUE) return TRUE otherwise FALSE
if(FALSE || FALSE || FALSE) return FALSE otherwise TRUE
Logical operator and &&
If all conditions/operands is TRUE return TRUE, otherwise return FALSE
Logical operator or ||
The logical OR operator (||) returns the boolean value true if either or both operands is true and returns false otherwise.
If one operands is TRUE, condition is TRUE:
rev
if(TRUE && TRUE && TRUE) return TRUE otherwise FALSE
if(FALSE || FALSE || FALSE) return FALSE otherwise TRUE
Logical operator and &&
If all conditions/operands is TRUE return TRUE, otherwise return FALSE
if( true and true and true){
// return true - do something
}
int a = 6;
if(a == 6 && a == 6 ) {
// if TRUE
// true && true return true, do something
}
if(a == 6 && a == 5){
// nothing, not attended
}else{
// true && false return false, or false && false return false
// do something
}
Logical operator or ||
The logical OR operator (||) returns the boolean value true if either or both operands is true and returns false otherwise.
If one operands is TRUE, condition is TRUE:
if(FALSE OR FALSE OR TRUE) return TRUE
if(FALSE OR TRUE OR FALSE) return TRUE
if(FALSE OR FALSE OR FALSE) return FALSE
int a = 6;
if(a==6 || a==5){ // TRUE || FALSE return TRUE
//if return TRUE
//one from operadns is TRUE return true, do something
}
if(a==5 || a==4){ // FALSE || FALSE return FALSE
// not attended
}else{
//if return FALSE, do something
}
rev
// in strings.xml
<string name="myStringWithTags"><![CDATA[<b>some text..</b> other tags ...]]></string>
<string name="myStringWithPattern"><![CDATA[<b>%s</b> other tags ...]]></string>
// in Activity.class
String sHtmlText = this.getApplicationContext().getString(R.string.myStringTags);
sHtmlText = this.getApplicationContext().getString(R.string.myStringWithPattern,"replace %s with this text");
Get key by value from Map Java Android example
MainClass.java
MainClass.java
import java.util.HashSet;
import java.util.Iterator;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;
import java.util.TreeMap;
public class MainClass {
public static void main(String[] arg) {
// english;germany dictionary
String[] arrayOfString = { "one;eine", "two;zwei", "two sets of;zwei"
, "three;drei", "four;vier" };
Map<String, String> map = new TreeMap<String, String>();
for (String s : arrayOfString) {
String[] array = s.split(";");
String sKey = "", sValue = "";
if (array.length > 1) {
sKey = array[0];
sValue = array[1];
map.put(sKey, sValue);
}
}
if (map.containsValue("zwei")) {
Set<String> references = getKeysByValue(map, "zwei");
Iterator<String> it = references.iterator();
while (it.hasNext()) {
String key = (String) it.next();
String value = map.get(key);
System.out.println(key + " = " + value);
}
}
}
public static <T, E> Set<T> getKeysByValue(Map<T, E> map, E value) {
Set<T> keys = new HashSet<T>();
for (Entry<T, E> entry : map.entrySet()) {
if (entry.getValue().equals(value)) {
keys.add(entry.getKey());
}
}
return keys;
}
}
/*
two = zwei
two sets of = zwei
*/
Editace: 2013-12-09 13:10:11
Počet článků v kategorii: 396
Url:create-monochromatic-bitmap-android-example
